Advertisements
Advertisements
Question
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
Sum
Advertisements
Solution
`((2"m")/(3"n") + (3"n")/(2"m"))^3`
= `((2"m")/(3"n"))^3 + ((3"n")/(2"m"))^3 + 3((2"m")/(3"n"))((3"n")/(2"m"))((2"m")/(3"n") + (3"n")/(2"m"))`
= `(8"m"^3)/(27"n"^3) + (27"n"^3)/(8"m"^3) + (2"m")/"n" + (9"n")/(2"m")`.
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand.
(7 + m)3
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
Use property to evaluate : 383 + (-26)3 + (-12)3
If a ≠ 0 and `a - 1/a` = 3 ; find `a^2 + 1/a^2`
If a ≠ 0 and `a - 1/a` = 4; find: `(a^2 + 1/a^2)`
If a ≠ 0 and `a - 1/a` = 4 ; find : `( a^4 + 1/a^4 )`
If p - q = -1 and pq = -12, find p3 - q3
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Expand: (3x + 4y)3.
Expand: `((2m)/n + n/(2m))^3`.
