Advertisements
Advertisements
प्रश्न
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
बेरीज
Advertisements
उत्तर
`((2"m")/(3"n") + (3"n")/(2"m"))^3`
= `((2"m")/(3"n"))^3 + ((3"n")/(2"m"))^3 + 3((2"m")/(3"n"))((3"n")/(2"m"))((2"m")/(3"n") + (3"n")/(2"m"))`
= `(8"m"^3)/(27"n"^3) + (27"n"^3)/(8"m"^3) + (2"m")/"n" + (9"n")/(2"m")`.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Expand.
(7x + 8y)3
Expand.
(52)3
Find the cube of : 5a + 3b
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes.
Find the cube of: `4"p" - (1)/"p"`
If `9"a"^2 + (1)/(9"a"^2) = 23`; find the value of `27"a"^3 + (1)/(27"a"^3)`
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
If x + 2y = 5, then show that x3 + 8y3 + 30xy = 125.
Expand: (41)3
