Advertisements
Advertisements
प्रश्न
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
बेरीज
Advertisements
उत्तर
`((2"m")/(3"n") + (3"n")/(2"m"))^3`
= `((2"m")/(3"n"))^3 + ((3"n")/(2"m"))^3 + 3((2"m")/(3"n"))((3"n")/(2"m"))((2"m")/(3"n") + (3"n")/(2"m"))`
= `(8"m"^3)/(27"n"^3) + (27"n"^3)/(8"m"^3) + (2"m")/"n" + (9"n")/(2"m")`.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Simplify.
(3r − 2k)3 + (3r + 2k)3
Find the cube of : 5a + 3b
If a + 2b + c = 0; then show that: a3 + 8b3 + c3 = 6abc.
Use property to evaluate : 133 + (-8)3 + (-5)3
Use property to evaluate : 73 + 33 + (-10)3
If a ≠ 0 and `a - 1/a` = 4; find: `(a^2 + 1/a^2)`
Find the cube of: `4"p" - (1)/"p"`
If `x + (1)/x = 5`, find the value of `x^2 + (1)/x^2, x^3 + (1)/x^3` and `x^4 + (1)/x^4`.
If 2a - 3b = 10 and ab = 16; find the value of 8a3 - 27b3.
Expand (52)3
