Find the Cube Of: 4 P − 1 P - Mathematics

Find the cube of: `4"p" - (1)/"p"`

योग

`(4"p" - (1)/"p")^3`

= `(4"p")^3 - (1/"p")^3 - 3(4"p") (1/"p") (4"p" - 1/"p")`

= `64"p"^3 - (1)/"P"^3 - 48"p" + (12)/"p"`.

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अध्याय 4: Expansions - Exercise 4.2

अध्याय 4 Expansions
Exercise 4.2 | Q 1.4

Find the cube of: `( 3a - 1/a ) (a ≠ 0 )`

If `a + 1/a` = p and a ≠ 0; then show that:

`a^3 + 1/a^3 = p(p^2 - 3)`

If a + 2b = 5; then show that : a³ + 8b³ + 30ab = 125.

Use property to evaluate : 13³ + (-8)³ + (-5)³

Use property to evaluate : 7³ + 3³ + (-10)³

Use property to evaluate : 9³ - 5³ - 4³

If `5x + (1)/(5x) = 7`; find the value of `125x^3 + (1)/(125x^3)`.

If `9"a"^2 + (1)/(9"a"^2) = 23`; find the value of `27"a"^3 + (1)/(27"a"^3)`

If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`

Expand: (x + 3)³.