Find the Cube Of: 4 P − 1 P

Find the cube of: `4"p" - (1)/"p"`

योग

`(4"p" - (1)/"p")^3`

= `(4"p")^3 - (1/"p")^3 - 3(4"p") (1/"p") (4"p" - 1/"p")`

= `64"p"^3 - (1)/"P"^3 - 48"p" + (12)/"p"`.

shaalaa.com

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions - Exercise 4.2

अध्याय 4 Expansions
Exercise 4.2 | Q 1.4

If `a^2 + 1/a^2` = 18; a ≠ 0 find :

(i) `a - 1/a`

(ii) `a^3 - 1/a^3`

If a + 2b = 5; then show that : a³ + 8b³ + 30ab = 125.

Expand : (3x - 5y - 2z) (3x - 5y + 2z)

If a ≠ 0 and `a - 1/a` = 4 ; find : `( a^3 - 1/a^3 )`

If `9"a"^2 + (1)/(9"a"^2) = 23`; find the value of `27"a"^3 + (1)/(27"a"^3)`

If `"a" + (1)/"a" = "p"`; then show that `"a"^3 + (1)/"a"^3 = "p"("p"^2 - 3)`

If a + b + c = 0; then show that a³ + b³ + c³ = 3abc.

If a + 2b + c = 0; then show that a³ + 8b³ + c³ = 6abc

Expand: (x + 3)³.

Expand (52)³