Advertisements
Advertisements
प्रश्न
Find the cube of: `3"a" + (1)/(3"a")`
योग
Advertisements
उत्तर
`(3"a" + 1/(3"a"))^3`
= `(3"a")^3 + (1/(3"a"))^3 + 3 (3"a") (1/(3"a")) (3"a" + 1/(3"a"))`
= `27"a"^3 + (1)/(27"a"^3) + 9"a" + (1)/"a"`.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand.
(101)3
Find the cube of: `( 3a - 1/a ) (a ≠ 0 )`
Use property to evaluate : 383 + (-26)3 + (-12)3
Find the cube of: 4x + 7y
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
If `"r" - (1)/"r" = 4`; find : `"r"^3 - (1)/"r"^3`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Expand (2a + 5)3
