Advertisements
Advertisements
प्रश्न
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
योग
Advertisements
उत्तर
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
= `("a")3 + (1/"a")^3 + 3("a")(1/"a")("a" + 1/"a") - [("a")^3 - (1/"a")^3 = -3("a")(1/"a")("a" - 1/"a")]`
= `"a"^3 + (1)/"a"^3 + 3("a" + 1/"a") - ["a"^3 - 1/"a"^3 - 3("a" - 1/"a")]`
= `"a"^3 + (1)/"a"^3 + 3"a" + (3)/"a" - "a"^3 + (1)/"a"^3 + 3"a" - (3)/"a"`
= `(2)/"a"^3 + 6"a"`.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand.
(52)3
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
If `a + 1/a` = p and a ≠ 0; then show that:
`a^3 + 1/a^3 = p(p^2 - 3)`
If a ≠ 0 and `a - 1/a` = 3 ; find `a^2 + 1/a^2`
If `"p" + (1)/"p" = 6`; find : `"p"^3 + (1)/"p"^3`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
If a + b = 5 and ab = 2, find a3 + b3.
Expand: (3x + 4y)3.
Expand: (41)3
Expand (52)3
