Advertisements
Advertisements
प्रश्न
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Advertisements
उत्तर
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
= `("a")3 + (1/"a")^3 + 3("a")(1/"a")("a" + 1/"a") - [("a")^3 - (1/"a")^3 = -3("a")(1/"a")("a" - 1/"a")]`
= `"a"^3 + (1)/"a"^3 + 3("a" + 1/"a") - ["a"^3 - 1/"a"^3 - 3("a" - 1/"a")]`
= `"a"^3 + (1)/"a"^3 + 3"a" + (3)/"a" - "a"^3 + (1)/"a"^3 + 3"a" - (3)/"a"`
= `(2)/"a"^3 + 6"a"`.
APPEARS IN
संबंधित प्रश्न
Simplify.
(3r − 2k)3 + (3r + 2k)3
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
If 2x - 3y = 10 and xy = 16; find the value of 8x3 - 27y3.
If a ≠ 0 and `a - 1/a` = 3 ; find `a^2 + 1/a^2`
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
Find the cube of: 2a - 5b
If `"a" - (1)/"a" = 7`, find `"a"^2 + (1)/"a"^2 , "a"^2 - (1)/"a"^2` and `"a"^3 - (1)/"a"^3`
If x3 + y3 = 9 and x + y = 3, find xy.
Expand: (41)3
If `x^2 + 1/x^2` = 23, then find the value of `x + 1/x` and `x^3 + 1/x^3`
