Advertisements
Advertisements
प्रश्न
If a + b = 5 and ab = 2, find a3 + b3.
योग
Advertisements
उत्तर
Using (a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 - 2ab
⇒ a2 + b2 = (5)2 - 2(2)
⇒ a2 + b2 = 25 - 4
⇒ a2 + b2 = 21
a3 + b3
= (a + b) (a2 + b2 - ab)
= (5) (21 - 2)
= (5) (19)
= 95.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand.
(7x + 8y)3
Simplify.
(3r − 2k)3 + (3r + 2k)3
Find the cube of : 3a- 2b
If a2 + `1/a^2 = 47` and a ≠ 0 find :
- `a + 1/a`
- `a^3 + 1/a^3`
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
If a + 2b + c = 0; then show that: a3 + 8b3 + c3 = 6abc.
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes.
Evaluate the following :
(3.29)3 + (6.71)3
Expand: (x + 3)3.
Expand (104)3
