Advertisements
Advertisements
प्रश्न
Expand.
`((5x)/y + y/(5x))^3`
Advertisements
उत्तर
`((5x)/y + y/(5x))^3`
(a + b)3 = a3 + 3a2b + 3ab2 + b3
= `((5x)/y)^3 + 3 xx ((5x)/y)^2 xx (y/(5x)) + 3 xx ((5x)/y) xx (y/(5x))^2 + (y/(5x))^3`
= `(125x^3)/(y^3) + 3 xx (25x^2)/(y^2) xx y/(5x) + 3 xx (5x)/y xx (y^2)/(25x^2) + y^3/(125x^3)`
= `(125x^3)/(y^3) + (3 xx 25x)/y xx 1/5 + 3 xx 5 xx y/(25x) + (y^3)/(125x^3)`
= `(125x^3)/(y^3) + (15x)/y + (3y)/(5x) + (y^3)/(125x^3)`
∴ `((5x)/y + y/(5x))^3 = (125x^3)/(y^3) + (15x)/y + (3y)/(5x) + (y^3)/(125x^3)`
संबंधित प्रश्न
Expand.
(k + 4)3
Find the cube of : 3a- 2b
If a + 2b = 5; then show that : a3 + 8b3 + 30ab = 125.
Use property to evaluate : 133 + (-8)3 + (-5)3
Use property to evaluate : 93 - 53 - 43
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
Find the cube of: `3"a" + (1)/(3"a")`
If `9"a"^2 + (1)/(9"a"^2) = 23`; find the value of `27"a"^3 + (1)/(27"a"^3)`
If p - q = -1 and pq = -12, find p3 - q3
Expand: `[x + 1/y]^3`
