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प्रश्न
Expand.
(7x + 8y)3
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उत्तर
(7x + 8y)3
= `(7x)^3 + 3 xx (7x)^2 xx (8y) + 3 xx (7x) xx (8y)^2 + (8y)^3` …[∵ (a + b)3 = a3 + 3a2b + 3ab2 + b3]
= `343x^3 + 3(49x^2)(8y) + 3(7x)(64y^2) + 512y^3`
= `343x^3 + 1176x^2y + 1344xy^2 + 512y^3`
संबंधित प्रश्न
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
If `a + 1/a` = p and a ≠ 0; then show that:
`a^3 + 1/a^3 = p(p^2 - 3)`
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
- Sum of these numbers
- Difference of their cubes
- Sum of their cubes.
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
If `"a" + (1)/"a" = "p"`; then show that `"a"^3 + (1)/"a"^3 = "p"("p"^2 - 3)`
If `("a" + 1/"a")^2 = 3`; then show that `"a"^3 + (1)/"a"^3 = 0`
If m - n = -2 and m3 - n3 = -26, find mn.
If `"a" + 1/"a"` = 6, then find the value of `"a"^3 + 1/"a"^3`
(p + q)(p2 – pq + q2) is equal to _____________
