Advertisements
Advertisements
प्रश्न
Expand.
(k + 4)3
योग
Advertisements
उत्तर
It is known that,
`(a+b)^3 = a^3 + 3a^2b +3ab^2 + b^3`
= (k + 4)3 = `(k)^3 + 3 xx (k)^2 xx (4) + 3 xx (k) xx (4)^2 + (4)^3`
= `(k)^3 + 12(k)^2 + 3(k)(16) + 64`
= `k^3 + 12k^2 + 48k + 64`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Expand.
(101)3
Find the cube of: `( 3a - 1/a ) (a ≠ 0 )`
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
- Sum of these numbers
- Difference of their cubes
- Sum of their cubes.
Find the cube of: `"a" - (1)/"a" + "b"`
If m - n = -2 and m3 - n3 = -26, find mn.
Expand: (3x + 4y)3.
Expand: `((2m)/n + n/(2m))^3`.
Expand (3 + m)3
Expand (3p + 4q)3
a3 + b3 = (a + b)3 = __________
