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प्रश्न
Expand.
`(1/y + 4)(1/y - 9)`
योग
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उत्तर
`(1/y + 4)(1/y - 9)`
= `(1/y)^2 + {4 + (-9)}1/y + (4) xx (-9)`
= `1/y^2 + (-5) xx 1/y -36`
= `1/y^2 -5/y - 36`
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