Advertisements
Advertisements
प्रश्न
If `"m"^2 + (1)/"m"^2 = 51`; find the value of `"m"^3 - (1)/"m"^3`
Advertisements
उत्तर
`"m"^2 + (1)/"m"^2 = 51`
We know that
`("m" - 1/"m")^2`
= `"m"^2 + (1)/"m"^2 - 2`
⇒ `("m" - 1/"m")^2` = 51 - 2
⇒ `("m" - 1/"m")^2` = 49 = 72
⇒ `"m" - 1/"m"` = 7
⇒ `("m" - 1/"m")^3` = 73
⇒ `"m"^3 - (1)/"m"^3 - 3("m" - 1/"m")` = 343
⇒ `"m"^3 - (1)/"m"^3 - 3 xx 7` = 343
⇒ `"m"^3 - (1)/"m"^3`
= 343 + 21
= 364.
APPEARS IN
संबंधित प्रश्न
Expand.
(7x + 8y)3
Expand.
`(2m + 1/5)^3`
Simplify.
(3r − 2k)3 + (3r + 2k)3
If a2 + `1/a^2 = 47` and a ≠ 0 find :
- `a + 1/a`
- `a^3 + 1/a^3`
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
- Sum of these numbers
- Difference of their cubes
- Sum of their cubes.
Expand : (3x - 5y - 2z) (3x - 5y + 2z)
If 2x - 3y = 10 and xy = 16; find the value of 8x3 - 27y3.
If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a"^3 + (1)/"a"^3`
Find 27a3 + 64b3, if 3a + 4b = 10 and ab = 2
Expand (52)3
