Advertisements
Advertisements
प्रश्न
If `"p" + (1)/"p" = 6`; find : `"p"^3 + (1)/"p"^3`
योग
Advertisements
उत्तर
`("p" + 1/"p")^3`
= `"p"^3 + (1)/"p"^3 + 3 ("p" + 1/"p")`
⇒ 216 = `"p"^3 + (1)/"p"^3 + 3(6)`
⇒ `"p"^3 + (1)/"p"^3`
= 216 - 18
= 198.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the cube of : 5a + 3b
If `a + 1/a` = p and a ≠ 0; then show that:
`a^3 + 1/a^3 = p(p^2 - 3)`
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
If a ≠ 0 and `a - 1/a` = 4 ; find : `( a^4 + 1/a^4 )`
If 2a - 3b = 10 and ab = 16; find the value of 8a3 - 27b3.
Simplify:
(a + b)3 + (a - b)3
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Evaluate the following :
(8.12)3 - (3.12)3
Expand: (41)3
If `"a" + 1/"a"` = 6, then find the value of `"a"^3 + 1/"a"^3`
