Advertisements
Advertisements
प्रश्न
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
योग
Advertisements
उत्तर
`(x^3 - (1)/x)^3`
= `x^3 - (1)/x^3 - 3(x - 1/x)`
⇒ 64 = `x^3 - (1)/x^3 - 3(4)`
⇒ `x^3 - (1)/x^3`
= 64 + 12
= 76.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand.
`(2m + 1/5)^3`
Find the cube of : 5a + 3b
If a + 2b = 5; then show that : a3 + 8b3 + 30ab = 125.
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
Expand : (3x - 5y - 2z) (3x - 5y + 2z)
If `("a" + 1/"a")^2 = 3`; then show that `"a"^3 + (1)/"a"^3 = 0`
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Find 27a3 + 64b3, if 3a + 4b = 10 and ab = 2
If `"a" + 1/"a"` = 6, then find the value of `"a"^3 + 1/"a"^3`
(p + q)(p2 – pq + q2) is equal to _____________
