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प्रश्न
Expand.
`(2m + 1/5)^3`
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उत्तर
Here, a = 2m, b = `1/5`
We know that,
(a + b)3 = a3 + 3a2b + 3ab2 + b3
∴ `(2m + 1/5)^3 = (2m)^3 + 3(2m)^2(1/5) + 3(2m)(1/5)^2 + (1/5)^3`
= `2^3m^3 + 3/5(2^2 m^2) + 6m xx 1^2/5^2 + 1^3/5^3`
= `8m^3 + 12/5 m^2 + (6m)/25 + 1/125`
∴ `(2m + 1/5)^3 = 8m^3 + 12/5 m^2 + 6/25m + 1/125`
संबंधित प्रश्न
Expand.
(7x + 8y)3
Find the cube of: `( 3a - 1/a ) (a ≠ 0 )`
If `a + 1/a` = p and a ≠ 0; then show that:
`a^3 + 1/a^3 = p(p^2 - 3)`
If a + 2b + c = 0; then show that: a3 + 8b3 + c3 = 6abc.
If a ≠ 0 and `a- 1/a` = 3 ; Find :
`a^3 - 1/a^3`
Find the cube of: 2a - 5b
If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a"^3 + (1)/"a"^3`
If `9"a"^2 + (1)/(9"a"^2) = 23`; find the value of `27"a"^3 + (1)/(27"a"^3)`
If p - q = -1 and pq = -12, find p3 - q3
Expand: (3x + 4y)3.
