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प्रश्न
Expand: `[x + 1/y]^3`
योग
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उत्तर
(a + b)3 = a3 + b3 + 3ab(a + b)
`[x + 1/y]^3 = x^3 + 1/y^3 + 3 xx x xx 1/y(x + 1/y)`
= `x^3 + 1/y^3 + (3x)/y(x + 1/y)`
= `x^3 + 1/y^3 + (3x^2)/y + (3x)/(y^2)`
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