Advertisements
Advertisements
प्रश्न
Expand: (3a – 4b)3
योग
Advertisements
उत्तर
(a – b)3 = a3 – b3 – 3ab(a – b)
(3a – 4b)3 = (3a)3 – (4b)3 – 3(3a)(4b)(3a – 4b)
= 27a3 – 64b3 – 36ab(3a – 4b)
= 27a3 – 64b3 – 108a2b + 144ab2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand.
(198)3
Expand.
`(2p - 1/(2p))^3`
Expand.
`(x/3 - 3/x)^3`
Expand (x - 2)3.
Expand (4p - 5q)3
Find the cube of 99 using the expansion formula.
Simplify.
(2x + 3y)3 - (2x - 3y)3
Find x3 – y3, if x – y = 5 and xy = 14.
If `(y - 1/y)^3` = 27, then find the value of `y^3 - 1/y^3`
Expand (48)3
