Advertisements
Advertisements
प्रश्न
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes.
Advertisements
उत्तर
Let two numbers be a and b.
Given,
Sum of numbers = 9 and Product = 20.
∴ a + b = 9 and ab = 20.
(i) Sum of squares = a2 + b2
By formula,
⇒ (a + b)2 = a2 + b2 + 2ab
Substituting values we get :
⇒ 92 = a2 + b2 + 2 × 20
⇒ 81 = a2 + b2 + 40
⇒ a2 + b2 = 81 - 40 = 41.
Hence, sum of squares = 41.
(ii) Sum of cubes = a3 + b3
By formula,
⇒ (a + b)3 = a3 + b3 + 3ab(a + b)
⇒ 93 = a3 + b3 + 3 × 20 × 9
⇒ 729 = a3 + b3 + 540
⇒ a3 + b3 = 729 − 540
⇒ a3 + b3 = 189.
Hence, a3 + b3 = 189.
APPEARS IN
संबंधित प्रश्न
If a2 + `1/a^2 = 47` and a ≠ 0 find :
- `a + 1/a`
- `a^3 + 1/a^3`
If `( a + 1/a )^2 = 3 "and a ≠ 0; then show:" a^3 + 1/a^3 = 0`.
Find the cube of: `4"p" - (1)/"p"`
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
If `("a" + 1/"a")^2 = 3`; then show that `"a"^3 + (1)/"a"^3 = 0`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
If x3 + y3 = 9 and x + y = 3, find xy.
If x + 2y = 5, then show that x3 + 8y3 + 30xy = 125.
Evaluate the following :
(5.45)3 + (3.55)3
Expand (3 + m)3
