Simplify: (2x + Y)(4x2 - 2xy + Y2)

Simplify:
(2x + y)(4x² - 2xy + y²)

योग

(2x + y)(4x² - 2xy + y²)
= 2x(4x² - 2xy + y²) + y(4x² - 2xy + y²)
= 8x³ - 4x²y + 2xy² + 4x²y - 2xy² + y2
= 8x³ + y³.

shaalaa.com

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions - Exercise 4.2

अध्याय 4 Expansions
Exercise 4.2 | Q 24.07

Factorise the following using appropriate identity:

`x^2 - y^2/100`

Factorise:

4x² + 9y² + 16z² + 12xy – 24yz – 16xz

Factorise the following:

27 – 125a³ – 135a + 225a²

If x + y + z = 0, show that x³ + y³ + z³ = 3xyz.

Evaluate following using identities:

991 ☓ 1009

If \[x - \frac{1}{x} = - 1\] find the value of \[x^2 + \frac{1}{x^2}\]

Find the cube of the following binomials expression :

\[\frac{1}{x} + \frac{y}{3}\]

Use the direct method to evaluate :
`(3/5"a"+1/2)(3/5"a"-1/2)`

If `x^2 + (1)/x^2 = 18`; find : `x - (1)/x`

Simplify:
(2x - 4y + 7)(2x + 4y + 7)