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Question
Find the area of triangle AGF
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Solution
Area of a triangle = `1/2[(x_1y_2 + x_2y_3 + x_3y_1) - (x_2y_1 + x_3y_2 + x_1y_3)]`
Area of ∆AGF = `1/2[(-2.5 - 13.5 - 6) - (-13.5 - 1 - 15)]`
= `1/2[-22 - (-29.5)]`
= `1/2[-22 + 29.5]`
= `1/2 xx 7.5`
= 3.75 sq.units
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