Advertisements
Advertisements
Question
A triangular shaped glass with vertices at A(– 5, – 4), B(1, 6) and C(7, – 4) has to be painted. If one bucket of paint covers 6 square feet, how many buckets of paint will be required to paint the whole glass, if only one coat of paint is applied
Advertisements
Solution
Given the vertices of the triangular glass is A (– 5, – 4), B (1, 6), and C (7, – 4)
Area of triangle ACB = `1/2[(x_1y_2 + x_2y_3 + x_3y_1) - (x_2y_1 + x_3y_2 + x_1y_3)]`

= `1/2[(20 + 42 - 4) - (-28 - 4 - 30)]`
= `1/2[58 - (- 62)]`
= `1/2 [58 + 62]`
= `1/2 xx 120`
= 60 sq. feet
Number of cans to paint 6 square feet = 1
∴ Number of cans = `60/6` = 10
⇒ Number of cans = 10
APPEARS IN
RELATED QUESTIONS
A triangle has sides 35 cm, 54 cm and 61 cm long. Find its area. Also, find the smallest of its altitudes ?
A hand fan is made by stitching lo equal size triangular strips of two different types of paper as shown in Fig. 12.28. The dimensions of equal strips are 25 cm, 25 cm and 14 cm. Find the area of each type of paper needed to make the hand fan.

Find the area of the triangle formed by the points
(1, – 1), (– 4, 6) and (– 3, – 5)
Find the area of triangle AGF
If (5, 7), (3, p) and (6, 6) are collinear, then the value of p is
The perimeter of a triangular plot is 600 m. If the sides are in the ratio 5 : 12 : 13, then find the area of the plot
The area of the isosceles triangle is `5/4 sqrt(11)` cm2, if the perimeter is 11 cm and the base is 5 cm.
The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field.
A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs 5 per m2. Find the cost of painting.
A field is in the shape of a trapezium having parallel sides 90 m and 30 m. These sides meet the third side at right angles. The length of the fourth side is 100 m. If it costs Rs 4 to plough 1 m2 of the field, find the total cost of ploughing the field.
