Advertisements
Advertisements
प्रश्न
A triangular shaped glass with vertices at A(– 5, – 4), B(1, 6) and C(7, – 4) has to be painted. If one bucket of paint covers 6 square feet, how many buckets of paint will be required to paint the whole glass, if only one coat of paint is applied
Advertisements
उत्तर
Given the vertices of the triangular glass is A (– 5, – 4), B (1, 6), and C (7, – 4)
Area of triangle ACB = `1/2[(x_1y_2 + x_2y_3 + x_3y_1) - (x_2y_1 + x_3y_2 + x_1y_3)]`
= `1/2[(20 + 42 - 4) - (-28 - 4 - 30)]`
= `1/2[58 - (- 62)]`
= `1/2 [58 + 62]`
= `1/2 xx 120`
= 60 sq. feet
Number of cans to paint 6 square feet = 1
∴ Number of cans = `60/6` = 10
⇒ Number of cans = 10
APPEARS IN
संबंधित प्रश्न
The perimeter of a triangle is 300 m. If its sides are in the ratio 3 : 5 : 7. Find the area of the triangle ?
The perimeter of a triangular field is 240 dm. If two of its sides are 78 dm and 50 dm, find the length of the perpendicular on the side of length 50 dm from the opposite vertex.
A rhombus sheet, whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs 5 per m2. Find the cost of painting.
Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.
Find the area of an isosceles triangle having the base x cm and one side y cm.
Find the area of the triangle formed by the points
(–10, –4), (–8, –1) and (–3, –5)
Using Heron’s formula, find the area of a triangle whose sides are 1.8 m, 8 m, 8.2 m
The area of the isosceles triangle is `5/4 sqrt(11)` cm2, if the perimeter is 11 cm and the base is 5 cm.
Find the area of a parallelogram given in figure. Also find the length of the altitude from vertex A on the side DC.
The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field.
