Advertisements
Advertisements
Question
A rhombus sheet, whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs 5 per m2. Find the cost of painting.
Advertisements
Solution
Given that,
Perimeter of a rhombus = 32 m
We know that,
Perimeter of rhombus = 4 × side
⇒ 49 = 32m
⇒ a = 8 m
Let AC = 10 = OA = `1/2`𝐴𝐶
= `1/2`×10
= 5𝑚
By using Pythagoras theorem:
∴`OB^2=AB^2-OA^2`
`⇒OB=sqrt(AB^2-OA^2)`
`⇒OB=sqrt(8^2-5^2)`
`⇒OB=sqrt(64-25)`
`⇒OB=sqrt(39m)`
Now, BD = 2OB = 2√39𝑚
∴ Area of sheet = `1/2`×𝐵𝐷×𝐴𝐶=`1/2`×2`sqrt(39)xx10sqrt(39)m^2`
∴ Cost of printing on both sides at the rate of Rs 5 per `m^2` = Rs 2 ×10`sqrt(39)`×5
= Rs. 625.00
APPEARS IN
RELATED QUESTIONS
The lengths of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 144 cm. Find the area of the triangle and the height corresponding to the longest side.
Find the area of an isosceles triangle having the base x cm and one side y cm.
Find the areas of the given plot. (All measures are in metres.)
A triangular shaped glass with vertices at A(– 5, – 4), B(1, 6) and C(7, – 4) has to be painted. If one bucket of paint covers 6 square feet, how many buckets of paint will be required to paint the whole glass, if only one coat of paint is applied
The area of triangle formed by the points (− 5, 0), (0, – 5) and (5, 0) is
Find the area of a triangle formed by the lines 3x + y – 2 = 0, 5x + 2y – 3 = 0 and 2x – y – 3 = 0
An advertisement board is in the form of an isosceles triangle with perimeter 36 m and each of the equal sides are 13 m. Find the cost of painting it at ₹ 17.50 per square metre.
The cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of Rs 3 per m2 is Rs 918.
Find the area of a parallelogram given in figure. Also find the length of the altitude from vertex A on the side DC.
How much paper of each shade is needed to make a kite given in the following figure, in which ABCD is a square with diagonal 44 cm.
