Advertisements
Advertisements
Question
Find the area of triangle FED
Advertisements
Solution
Area of a triangle = `1/2` [(x1y2 + x2y3 + x3y1) – (x2y1 + x3y2 + x1y3)]
Area of ∆FED = `1/2[(-2 + 4.5 + 3) - (4.5 + 1 - 6)]`
= `1/2[5.5 - (- 0.5)]`

= `1/2[5.5 + 0.5]`
= `1/2 xx 6`
= 3 sq.units
APPEARS IN
RELATED QUESTIONS
There is a slide in the park. One of its side walls has been painted in some colour with a message “KEEP THE PARK GREEN AND CLEAN” (see the given figure). If the sides of the wall are 15m, 11m, and 6m, find the area painted in colour.

The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.
Find the area of the shaded region in the given figure.

Find the area of a quadrilateral ABCD in which AB = 42 cm, BC = 21 cm, CD = 29 cm, DA =34 cm and diagonal BD =20 cm.
Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.
The area of triangle formed by the points (− 5, 0), (0, – 5) and (5, 0) is
A man walks near a wall, such that the distance between him and the wall is 10 units. Consider the wall to be the Y-axis. The path travelled by the man is
An advertisement board is in the form of an isosceles triangle with perimeter 36 m and each of the equal sides are 13 m. Find the cost of painting it at ₹ 17.50 per square metre.
The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. Find the area of the triangle.
In the following figure, ∆ABC has sides AB = 7.5 cm, AC = 6.5 cm and BC = 7 cm. On base BC a parallelogram DBCE of same area as that of ∆ABC is constructed. Find the height DF of the parallelogram.

