Advertisements
Advertisements
प्रश्न
Find the area of triangle AGF
Advertisements
उत्तर
Area of a triangle = `1/2[(x_1y_2 + x_2y_3 + x_3y_1) - (x_2y_1 + x_3y_2 + x_1y_3)]`
Area of ∆AGF = `1/2[(-2.5 - 13.5 - 6) - (-13.5 - 1 - 15)]`
= `1/2[-22 - (-29.5)]`
= `1/2[-22 + 29.5]`
= `1/2 xx 7.5`
= 3.75 sq.units
APPEARS IN
संबंधित प्रश्न
A triangle has sides 35 cm, 54 cm and 61 cm long. Find its area. Also, find the smallest of its altitudes ?
Find the area of a quadrilateral ABCD in which AB = 42 cm, BC = 21 cm, CD = 29 cm, DA =34 cm and diagonal BD =20 cm.
Find the area of the triangle formed by the points
(–10, –4), (–8, –1) and (–3, –5)
If the points A(– 3, 9), B(a, b) and C(4, – 5) are collinear and if a + b = 1, then find a and b
The sides of the triangular ground are 22 m, 120 m and 122 m. Find the area and cost of levelling the ground at the rate of ₹ 20 per m2
Find the area of the unshaded region
The semi-perimeter of a triangle having sides 15 cm, 20 cm and 25 cm is
The cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of Rs 3 per m2 is Rs 918.
The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field.
The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. Find the area of the triangle.
