Advertisements
Advertisements
प्रश्न
Find the area of triangle AGF
Advertisements
उत्तर
Area of a triangle = `1/2[(x_1y_2 + x_2y_3 + x_3y_1) - (x_2y_1 + x_3y_2 + x_1y_3)]`
Area of ∆AGF = `1/2[(-2.5 - 13.5 - 6) - (-13.5 - 1 - 15)]`
= `1/2[-22 - (-29.5)]`
= `1/2[-22 + 29.5]`
= `1/2 xx 7.5`
= 3.75 sq.units
APPEARS IN
संबंधित प्रश्न
The perimeter of a triangular field is 240 dm. If two of its sides are 78 dm and 50 dm, find the length of the perpendicular on the side of length 50 dm from the opposite vertex.
The lengths of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 144 cm. Find the area of the triangle and the height corresponding to the longest side.
Find the area of a quadrilateral ABCD in which AB = 42 cm, BC = 21 cm, CD = 29 cm, DA =34 cm and diagonal BD =20 cm.
A hand fan is made by stitching lo equal size triangular strips of two different types of paper as shown in Fig. 12.28. The dimensions of equal strips are 25 cm, 25 cm and 14 cm. Find the area of each type of paper needed to make the hand fan.
Look at the measures shown in the adjacent figure and find the area of ☐ PQRS.
Find the area of the triangle formed by the points
(1, – 1), (– 4, 6) and (– 3, – 5)
Find the area of triangle FED
The area of a triangle is 5 sq. units. Two of its vertices are (2, 1) and (3, −2). The third vertex is (x, y) where y = x + 3. Find the coordinates of the third vertex.
From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. The lengths of the perpendiculars are 14 cm, 10 cm and 6 cm. Find the area of the triangle.
The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field.
