Advertisements
Advertisements
Question
Find the area of the following triangle:
Advertisements
Solution
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 2 cm
Area = `1/2 xx 3 xx 2`
= 3cm2
APPEARS IN
RELATED QUESTIONS
Find a relation between x and y if the points (x, y), (1, 2) and (7, 0) are collinear.
Find the area of a triangle whose vertices are
`(at_1^2,2at_1),(at_2^2,2at_2)` and `(at_3^2,2at_3)`
Two vertices of a triangle are (1, 2), (3, 5) and its centroid is at the origin. Find the coordinates of the third vertex.
Show that the points are the vertices of an isosceles right triangle.
For what values of k are the points A(8, 1) B(3, -2k) and C(k, -5) collinear.
Using integration, find the area of the triangle whose vertices are (2, 3), (3, 5) and (4, 4).
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is ______.
In the following figure, if PR = 12 cm, QR = 6 cm and PL = 8 cm, then QM is ______.
Ratio of the area of ∆WXY to the area of ∆WZY is 3 : 4 (see figure). If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.
In the following figure, triangle AEC is right-angled at E, B is a point on EC, BD is the altitude of triangle ABC, AC = 25 cm, BC = 7 cm and AE = 15 cm. Find the area of triangle ABC and the length of DB.
