Advertisements
Advertisements
Question
Find the missing value:
| Base | Height | Area of triangle |
| 15 cm | ______ | 87 cm2 |
Advertisements
Solution
| Base | Height | Area of triangle |
| 15 cm | 11.6 | 87 cm2 |
Explanation:
Area of Triangle = `1/2 xx "Base" xx "Height"`
b = 15 cm
h = ?
Area = `1/2 xx b xx h` = 87 cm2
`1/2 xx 15 xx h` = 87 cm2
h = `(87xx 2)/15`
h = 11.6 cm
Therefore, the height of triangle is 11.6 cm.
RELATED QUESTIONS
Find the area of the triangle ABC with A(1, −4) and mid-points of sides through A being (2, −1) and (0, −1).
For what value of x will the points (x, –1), (2, 1) and (4, 5) lie on a line ?
Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ΔABC.
(i) The median from A meets BC at D. Find the coordinates of point D.
(ii) Find the coordinates of the point P on AD such that AP: PD = 2:1
(iii) Find the coordinates of point Q and R on medians BE and CF respectively such that BQ: QE = 2:1 and CR: RF = 2:1.
(iv) What do you observe?
(v) If A(x1, y1), B(x2, y2), and C(x3, y3) are the vertices of ΔABC, find the coordinates of the centroid of the triangle.
Find the area of a triangle whose vertices are
(6,3), (-3,5) and (4,2)
For what value of x are the points A(−3, 12), B(7, 6) and C(x, 9) collinear.
For what value of y, are the points P(1, 4), Q(3,y) and R(-3, 16) are collinear ?
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is ______.
In the following figure, triangle AEC is right-angled at E, B is a point on EC, BD is the altitude of triangle ABC, AC = 25 cm, BC = 7 cm and AE = 15 cm. Find the area of triangle ABC and the length of DB.
Let a vector `αhati + βhatj` be obtained by rotating the vector `sqrt(3)hati + hatj` by an angle 45° about the origin in counter-clockwise direction in the first quadrant. Then the area of triangle having vertices (α, β), (0, β) and (0, 0) is equal to ______.
