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प्रश्न
Find the missing value:
| Base | Height | Area of triangle |
| 15 cm | ______ | 87 cm2 |
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उत्तर
| Base | Height | Area of triangle |
| 15 cm | 11.6 | 87 cm2 |
Explanation:
Area of Triangle = `1/2 xx "Base" xx "Height"`
b = 15 cm
h = ?
Area = `1/2 xx b xx h` = 87 cm2
`1/2 xx 15 xx h` = 87 cm2
h = `(87xx 2)/15`
h = 11.6 cm
Therefore, the height of triangle is 11.6 cm.
संबंधित प्रश्न
median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).
Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ΔABC.
(i) The median from A meets BC at D. Find the coordinates of point D.
(ii) Find the coordinates of the point P on AD such that AP: PD = 2:1
(iii) Find the coordinates of point Q and R on medians BE and CF respectively such that BQ: QE = 2:1 and CR: RF = 2:1.
(iv) What do you observe?
(v) If A(x1, y1), B(x2, y2), and C(x3, y3) are the vertices of ΔABC, find the coordinates of the centroid of the triangle.
Find the area of a triangle with vertices at the point given in the following:
(−2, −3), (3, 2), (−1, −8)
Show that the following sets of points are collinear.
(1, −1), (2, 1) and (4, 5)
Show that the following points are collinear:
A(8, 1), B(3, –4) and C(2, –5)
Show that ∆ ABC with vertices A (–2, 0), B (0, 2) and C (2, 0) is similar to ∆ DEF with vertices D (–4, 0), F (4, 0) and E (0, 4) ?
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
If the sides of a triangle are 3 cm, 4 cm and 5 cm, then the area is
Find the area of the trapezium PQRS with height PQ given in the following figure.
Triangles having the same base have equal area.
