Advertisements
Advertisements
प्रश्न
Find the missing value:
| Base | Height | Area of triangle |
| 15 cm | ______ | 87 cm2 |
Advertisements
उत्तर
| Base | Height | Area of triangle |
| 15 cm | 11.6 | 87 cm2 |
Explanation:
Area of Triangle = `1/2 xx "Base" xx "Height"`
b = 15 cm
h = ?
Area = `1/2 xx b xx h` = 87 cm2
`1/2 xx 15 xx h` = 87 cm2
h = `(87xx 2)/15`
h = 11.6 cm
Therefore, the height of triangle is 11.6 cm.
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the points A(k + 1, 2k), B(3k, 2k + 3) and (5k – 1, 5k) are collinear.
The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle.
Find the area of the triangle whose vertices are: (2, 3), (-1, 0), (2, -4)
Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle
Find the centre of a circle passing through the points (6, − 6), (3, − 7) and (3, 3).
Find the area of the following triangle:
Find the area of the quadrilaterals, the coordinates of whose vertices are (–3, 2), (5, 4), (7, –6) and (–5, –4).
The four vertices of a quadrilateral are (1, 2), (−5, 6), (7, −4) and (k, −2) taken in order. If the area of the quadrilateral is zero, find the value of k.
Show that the points (a + 5, a – 4), (a – 2, a + 3) and (a, a) do not lie on a straight line for any value of a.
The area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is ______.
