Advertisements
Advertisements
Question
Find the area of the following triangle:
Advertisements
Solution
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 4 cm
Area = `1/2 xx 3 xx 4`
= 6 cm2
APPEARS IN
RELATED QUESTIONS
A(4, - 6), B(3,- 2) and C(5, 2) are the vertices of a 8 ABC and AD is its median. Prove that the median AD divides Δ ABC into two triangles of equal areas.
median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).
Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ΔABC.
(i) The median from A meets BC at D. Find the coordinates of point D.
(ii) Find the coordinates of the point P on AD such that AP: PD = 2:1
(iii) Find the coordinates of point Q and R on medians BE and CF respectively such that BQ: QE = 2:1 and CR: RF = 2:1.
(iv) What do you observe?
(v) If A(x1, y1), B(x2, y2), and C(x3, y3) are the vertices of ΔABC, find the coordinates of the centroid of the triangle.
Find the area of the quadrilaterals, the coordinates of whose vertices are
(−3, 2), (5, 4), (7, −6) and (−5, −4)
Prove that (2, -2) (-2, 1) and (5, 2) are the vertices of a right-angled triangle. Find the area of the triangle and the length of the hypotenuse.
If the coordinates of the mid-points of the sides of a triangle are (3, 4) (4, 6) and (5, 7), find its vertices.
Show that the points A(–5, 6), B(3, 0) and C(9, 8) are the vertices of an isosceles right-angled triangle. Calculate its area.
For what value of y, are the points P(1, 4), Q(3,y) and R(-3, 16) are collinear ?
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
Show that the points (a + 5, a – 4), (a – 2, a + 3) and (a, a) do not lie on a straight line for any value of a.
