Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:
Advertisements
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 4 cm
Area = `1/2 xx 3 xx 4`
= 6 cm2
APPEARS IN
संबंधित प्रश्न
Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
Find the area of the triangle ABC with A(1, −4) and mid-points of sides through A being (2, −1) and (0, −1).
The coordinates of A, B, C are (6, 3), (–3, 5) and (4, – 2) respectively and P is any point (x, y). Show that the ratio of the areas of triangle PBC and ABC is
If A(–5, 7), B(–4, –5), C(–1, –6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD
Find the area of a triangle whose vertices are
(6,3), (-3,5) and (4,2)
For what value of k(k>0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k+1, 10) equal to 53 square units?
For what values of k are the points A(8, 1) B(3, -2k) and C(k, -5) collinear.
Find the area of ΔABC with vertices A(0, -1), B(2,1) and C(0, 3). Also, find the area of the triangle formed by joining the midpoints of its sides. Show that the ratio of the areas of two triangles is 4:1.
The points (0, 5), (0, –9) and (3, 6) are collinear.
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
