Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:

Advertisements
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 4 cm
Area = `1/2 xx 3 xx 4`
= 6 cm2
APPEARS IN
संबंधित प्रश्न
The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle.
Find the area of the triangle PQR with Q(3, 2) and the mid-points of the sides through Q being (2, –1) and (1, 2).
Find the equation of the line joining (1, 2) and (3, 6) using the determinants.
Find the area of the following triangle:

Find the area of the quadrilaterals, the coordinates of whose vertices are (–3, 2), (5, 4), (7, –6) and (–5, –4).
The four vertices of a quadrilateral are (1, 2), (−5, 6), (7, −4) and (k, −2) taken in order. If the area of the quadrilateral is zero, find the value of k.
If a ≠ b ≠ c, prove that the points (a, a2), (b, b2), (c, c2) can never be collinear.
Find the area of ΔABC with A(1, –4) and midpoints of sides through A being (2, –1) and (0, –1).
Find a relation between x and y, if the points A(2, 1), B(x, y) and C(7,5) are collinear.
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| 5 feet | ? | 20 sq.feet |
