Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:
Advertisements
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 2 cm
Area = `1/2 xx 3 xx 2`
= 3cm2
APPEARS IN
संबंधित प्रश्न
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
Find the missing value:
| Base | Height | Area of triangle |
| 15 cm | ______ | 87 cm2 |
The four vertices of a quadrilateral are (1, 2), (−5, 6), (7, −4) and (k, −2) taken in order. If the area of the quadrilateral is zero, find the value of k.
Prove that the points (2a, 4a), (2a, 6a) and `(2a + sqrt3a, 5a)` are the vertices of an equilateral triangle.
The point A divides the join of P (−5, 1) and Q(3, 5) in the ratio k:1. Find the two values of k for which the area of ΔABC where B is (1, 5) and C(7, −2) is equal to 2 units.
Find the centroid of the triangle whosw vertices is (1,4), (-1,1) and (3,2) .
Prove that the lines joining the middle points of the opposite sides of a quadrilateral and the join of the middle points of its diagonals meet in a point and bisect one another
If G(-2, 1) is the centroid of a ΔABC and two of its vertices are A(1, -6) and B(-5, 2) , find the third vertex of the triangle.
Prove that the points A (a,0), B( 0,b) and C (1,1) are collinear, if `( 1/a+1/b) =1`.
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is ______.
