Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:

Advertisements
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 2 cm
Area = `1/2 xx 3 xx 2`
= 3cm2
APPEARS IN
संबंधित प्रश्न
In each of the following find the value of 'k', for which the points are collinear.
(8, 1), (k, -4), (2, -5)
median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).
Find the area of the quadrilaterals, the coordinates of whose vertices are
(1, 2), (6, 2), (5, 3) and (3, 4)
Four points A (6, 3), B (−3, 5), C(4, −2) and D (x, 3x) are given in such a way that `(ΔDBG) /(ΔABG)=1/2,` find x
Find the angle subtended at the origin by the line segment whose end points are (0, 100) and (10, 0).
Find the value of x for which the points (x, −1), (2, 1) and (4, 5) are collinear ?
If the points A (x, y), B (3, 6) and C (−3, 4) are collinear, show that x − 3y + 15 = 0.
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| 5 feet | ? | 20 sq.feet |
Find the coordinates of the point Q on the x-axis which lies on the perpendicular bisector of the line segment joining the points A(–5, –2) and B(4, –2). Name the type of triangle formed by the points Q, A and B.
Find the missing value:
| Base | Height | Area of parallelogram |
| ______ | 15 cm | 154.5 cm2 |
