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Maharashtra State BoardSSC (English Medium) 10th Standard

Find the Ratio in Which Point T(–1, 6)Divides the Line Segment Joining the Points P(–3, 10) and Q(6, –8).

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Question

Find the ratio in which point T(–1, 6)divides the line segment joining the points P(–3, 10) and Q(6, –8).

Sum
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Solution

Let the ratio be k : 1.  
Using section formula we have

\[- 1 = \frac{6k - 3 \times 1}{k + 1}\]

\[ \Rightarrow - k - 1 = 6k - 3\]

\[ \Rightarrow - 1 + 3 = 6k + k\]

\[ \Rightarrow 2 = 7k\]

\[ \Rightarrow k = \frac{2}{7}\]

Thus, the required ratio is 2 : 7.

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Chapter 5: Co-ordinate Geometry - Practice Set 5.2 [Page 115]

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