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Question
Draw a line segment AB of length 7 cm. Using ruler and compasses, find a point P on AB such that `(AP)/(AB)=3/5`.
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Solution
It is given that`(AP)/(AB)=3/5`.
`therefore (AP)/(PB)=(AP)/(AB-AP)=3/(5-3)=3/2`
Thus, point P divides line segment AB in the ratio 3: 2.
To draw a line segment AB of length 7 cm and mark a point P (using ruler and compass) such that `(AP)/(PB)=3/5 i,e, (AP)/(PB)=3/2`, the following steps are to be followed:
Step 1: Draw line segment AB of length 7 cm and draw a ray AX making an acute angle with line segment AB.
Step 2: Locate 5 (2 + 3) points i.e., A1, A2, A3, A4 and A5 on AX such that AA1 = A1 A2 = A2 A3 and so on.
Step 3: Join BA5.
Step 4: Through point A3 , draw a line parallel to BA5 (by making an angle equal to ∠AA5 B) at A3 intersecting AB at point P.

Now, P is the required point on line segment AB of length 7 cm. This point satisfies the condition`(AP)/(AB)=3/5`.
