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Find the Ratio in Which Point T(–1, 6)Divides the Line Segment Joining the Points P(–3, 10) and Q(6, –8).

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प्रश्न

Find the ratio in which point T(–1, 6)divides the line segment joining the points P(–3, 10) and Q(6, –8).

योग
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उत्तर

Let the ratio be k : 1.  
Using section formula we have

\[- 1 = \frac{6k - 3 \times 1}{k + 1}\]

\[ \Rightarrow - k - 1 = 6k - 3\]

\[ \Rightarrow - 1 + 3 = 6k + k\]

\[ \Rightarrow 2 = 7k\]

\[ \Rightarrow k = \frac{2}{7}\]

Thus, the required ratio is 2 : 7.

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अध्याय 5: Co-ordinate Geometry - Practice Set 5.2 [पृष्ठ ११५]

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बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 5 Co-ordinate Geometry
Practice Set 5.2 | Q 3 | पृष्ठ ११५

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