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Construct an equilateral ∆ABC with side 5 cm. ∆ABC ~ ∆LMN, ratio the corresponding sides of triangle is 6 : 7, then construct ΔLMN and ΔABC - Geometry Mathematics 2

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प्रश्न

Construct an equilateral ∆ABC with side 5 cm. ∆ABC ~ ∆LMN, ratio the corresponding sides of triangle is 6 : 7, then construct ΔLMN and ΔABC

आकृति
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उत्तर


Analysis: ∆ABC ∼ ∆LMN

∴ `"AB"/"LM" = "BC"/"MN" = "AC"/"LN"`  ......[Corresponding sides of similar triangles]

∴ `5/"LM" = 5/"MN" = 5/"LN" = 6/7`   .....[Given]

∴ `5/"LM" = 6/7`

∴ LM = `(5 xx 7)/6`

∴ LM = 5.8 cm (approx)

∴ LM = MN = LN = 5.8 cm (approx)    .....[Equilateral triangle]

Steps of Construction:

  ∆ABC ∆PQR
i. Draw seg BC of 5 cm Draw seg MN of 5.8 cm
ii. Draw two arcs at 5 cm from point B and point C respectively. Draw two arcs at 5.8 cm from point M and point N respectively.
iii. Name the point of intersection of two arcs as A. Name the point of intersection of two arcs as L.
iv. Join seg AB and seg AC. Join seg LM and seg LN.
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अध्याय 4: Geometric Constructions - Q.3 (B)

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