Advertisements
Advertisements
Question
Find the radius of curvature of the convex surface of a plano-convex lens, whose focal length is 0.3 m and the refractive index of the material of the lens is 1.5.
Advertisements
Solution
The focal length of a combined lens can be determined by the formula
`1/f =(mu -1)(1/R_1 - 1/R_2)`
Here, R_2 =∞ and f =0.3m
`1/0.3 =( mu-1) xx 1/R_1`
`R_1 = 0.3(mu-1)`
`=0.3(1.5 -1)`
` =0.3 xx 0.5`
`= 0.15m`
`=15 cm`
APPEARS IN
RELATED QUESTIONS
What is the focal length of a convex lens of focal length 30 cm in contact with a concave lens of focal length 20 cm? Is the system a converging or a diverging lens? Ignore thickness of the lenses.
(a) At what distance should the lens be held from the figure in order to view the squares distinctly with the maximum possible magnifying power?
(b) What is the magnification in this case?
(c) Is the magnification equal to the magnifying power in this case? Explain.

What is the power of a convex lens of focal length 0.5 m?
What is the nature of a lens whose power is, −4 D?
A lens has a focal length of, −10 cm. What is the power of the lens and what is its nature?
How is the sign (+ or -) of power of a lens related to its divergent or convergent action?
Define power of a lens. Write its units. Deduce the relation `1/f =1/f_1 +1/f_2`for two thin lenses kept in contact coaxially.
A convex lens is of focal length 20 cm. Find its power.
An object is kept at a distance of 1m from a lens of power +2D:
- Identify the type of lens.
- Calculate its focal length and distance of the image formed.
The lens of power + 1·0 D is ______.
