Advertisements
Advertisements
प्रश्न
Find the radius of curvature of the convex surface of a plano-convex lens, whose focal length is 0.3 m and the refractive index of the material of the lens is 1.5.
Advertisements
उत्तर
The focal length of a combined lens can be determined by the formula
`1/f =(mu -1)(1/R_1 - 1/R_2)`
Here, R_2 =∞ and f =0.3m
`1/0.3 =( mu-1) xx 1/R_1`
`R_1 = 0.3(mu-1)`
`=0.3(1.5 -1)`
` =0.3 xx 0.5`
`= 0.15m`
`=15 cm`
APPEARS IN
संबंधित प्रश्न
The focal length of a convex lens is 25 cm. What is its power?
What is the nature of a lens whose power is, −4 D?
State the condition for the following a ray passes undeviated through the lens .
A convex lens produces a double size real image when an object is placed at a distance of 18 cm from it. Where should the object be placed to produce a triple size real image?

The above lens has a focal length of 10 cm. The object of height 2 mm is placed at a distance of 5 cm from the pole. Find the height of the image.
The power of a lens is defined as the:
A negative power of a lens indicates a:
When a lens is placed in a liquid, the total power of the lens is:
If the refractive index of the lens material is less than that of the surrounding liquid (\[n_2 < n_1\]), then:
A concave lens has:
