Advertisements
Advertisements
प्रश्न
Find the radius of curvature of the convex surface of a plano-convex lens, whose focal length is 0.3 m and the refractive index of the material of the lens is 1.5.
Advertisements
उत्तर
The focal length of a combined lens can be determined by the formula
`1/f =(mu -1)(1/R_1 - 1/R_2)`
Here, R_2 =∞ and f =0.3m
`1/0.3 =( mu-1) xx 1/R_1`
`R_1 = 0.3(mu-1)`
`=0.3(1.5 -1)`
` =0.3 xx 0.5`
`= 0.15m`
`=15 cm`
APPEARS IN
संबंधित प्रश्न
Give the usual name for the following:
A point inside a lens through which the light passes undeviated.
A converging lens has focal length of 50 mm. What is the power of the lens?
How is the sign (+ or -) of power of a lens related to its divergent or convergent action?
On reducing the focal length of a lens, its power ______.
How does focal length of a lens change when red light incident on it is replaced by violet light? Give reason for your answer.
A symmetric double convex lens in cut in two equal parts by a plane perpendicular to the principal axis. If the power of the original lens was 4 D, the power a cut-lens will be
A convex lens produces a double size real image when an object is placed at a distance of 18 cm from it. Where should the object be placed to produce a triple size real image?
How is accommodation produced?
The following diagram shows the object O and the image I formed by a lens. Copy the diagram and on it mark the positions of the lens LL’ and focus (F). Name the lens.

A point object is placed at O in front of a glass sphere as shown in figure.

Show the formation of the image by the sphere.
