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Question
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
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Solution
x = log t y = sin t
`"dx"/"dt" = 1/"t"` `"dy"/"dt"` = cos t
`"dy"/"dx" = ("dy"/"dt")/("dx"/"dt")`
`= (cos "t")/(1/"t")` = t cos t
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