Advertisements
Advertisements
Question
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Advertisements
Solution
Let y = `(sqrtx + 1/sqrtx)^2`
`x + 1/x + 2 * sqrtx * 1/sqrtx`
y = `x + 1/x + 2`
`"dy"/"dx" = 1 - 1/x^2 + 0 = 1 - 1/x^2`
APPEARS IN
RELATED QUESTIONS
Differentiate the following with respect to x.
(x2 – 3x + 2) (x + 1)
Differentiate the following with respect to x.
x4 – 3 sin x + cos x
Differentiate the following with respect to x.
`(x^2 + x + 1)/(x^2 - x + 1)`
Differentiate the following with respect to x.
x sin x
If `xsqrt(1 + y) + ysqrt(1 + x)` = 0 and x ≠ y, then prove that `"dy"/"dx" = - 1/(x + 1)^2`
If 4x + 3y = log(4x – 3y), then find `"dy"/"dx"`
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Differentiate sin3x with respect to cos3x.
Differentiate sin2x with respect to x2.
Find y2 for the following function:
y = e3x+2
