Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Advertisements
उत्तर
Let y = `(sqrtx + 1/sqrtx)^2`
`x + 1/x + 2 * sqrtx * 1/sqrtx`
y = `x + 1/x + 2`
`"dy"/"dx" = 1 - 1/x^2 + 0 = 1 - 1/x^2`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
Differentiate the following with respect to x.
x sin x
Differentiate the following with respect to x.
sin(x2)
Differentiate the following with respect to x.
`1/sqrt(1 + x^2)`
Differentiate the following with respect to x.
xsin x
Differentiate the following with respect to x.
(sin x)tan x
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Differentiate sin3x with respect to cos3x.
If = a cos mx + b sin mx, then show that y2 + m2y = 0.
