Advertisements
Advertisements
प्रश्न
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
Advertisements
उत्तर
x = log t y = sin t
`"dx"/"dt" = 1/"t"` `"dy"/"dt"` = cos t
`"dy"/"dx" = ("dy"/"dt")/("dx"/"dt")`
`= (cos "t")/(1/"t")` = t cos t
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
x4 – 3 sin x + cos x
Differentiate the following with respect to x.
x sin x
Differentiate the following with respect to x.
x3 ex
If `xsqrt(1 + y) + ysqrt(1 + x)` = 0 and x ≠ y, then prove that `"dy"/"dx" = - 1/(x + 1)^2`
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Find y2 for the following function:
y = e3x+2
If y = 500e7x + 600e-7x, then show that y2 – 49y = 0.
If y = sin(log x), then show that x2y2 + xy1 + y = 0.
If xy . yx , then prove that `"dy"/"dx" = y/x((x log y - y)/(y log x - x))`
