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प्रश्न
Differentiate the following with respect to x.
ex (x + log x)
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उत्तर
Let y = ex (x + log x)
`"dy"/"dx" = e^x "d"/"dx" (x + log x) + (x + log x) "d"/"dx" (e^x)`
`= e^x (1 + 1/x) + (x + log x)e^x`
`= e^x [1 + 1/x + x + log x]`
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