Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
ex (x + log x)
Advertisements
उत्तर
Let y = ex (x + log x)
`"dy"/"dx" = e^x "d"/"dx" (x + log x) + (x + log x) "d"/"dx" (e^x)`
`= e^x (1 + 1/x) + (x + log x)e^x`
`= e^x [1 + 1/x + x + log x]`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
cos2 x
Differentiate the following with respect to x.
`sqrt(1 + x^2)`
Differentiate the following with respect to x.
(ax2 + bx + c)n
Differentiate the following with respect to x.
xsin x
Differentiate the following with respect to x.
(sin x)x
Differentiate the following with respect to x.
(sin x)tan x
Find `"dy"/"dx"` of the following function:
x = a cos3θ, y = a sin3θ
Differentiate sin3x with respect to cos3x.
Find y2 for the following function:
x = a cosθ, y = a sinθ
If y = 500e7x + 600e-7x, then show that y2 – 49y = 0.
