Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
ex (x + log x)
Advertisements
उत्तर
Let y = ex (x + log x)
`"dy"/"dx" = e^x "d"/"dx" (x + log x) + (x + log x) "d"/"dx" (e^x)`
`= e^x (1 + 1/x) + (x + log x)e^x`
`= e^x [1 + 1/x + x + log x]`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
cos3 x
Differentiate the following with respect to x.
(ax2 + bx + c)n
If 4x + 3y = log(4x – 3y), then find `"dy"/"dx"`
Differentiate the following with respect to x.
`sqrt(((x - 1)(x - 2))/((x - 3)(x^2 + x + 1)))`
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Find y2 for the following function:
y = log x + ax
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
