Advertisements
Advertisements
प्रश्न
Find `"dy"/"dx"` of the following function:
x = ct, y = `c/t`
Advertisements
उत्तर
x = ct, y = `"c"/"t"`
`"dx"/"dt"` = c `"dy"/"dt" = "c"((-1)/"t"^2)`
`"dy"/"dt" = ("dy"/"dt")/("dx"/"dt") = ("c"((-1)/"t"^2))/"c" = (-1)/t^2`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
`e^x/(1 + x)`
Differentiate the following with respect to x.
ex (x + log x)
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
sin2 x
Differentiate the following with respect to x.
`sqrt(1 + x^2)`
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
Differentiate sin2x with respect to x2.
If xy . yx , then prove that `"dy"/"dx" = y/x((x log y - y)/(y log x - x))`
