Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
x sin x
Advertisements
उत्तर
Let y = x sin x
`"dy"/"dx" = x "d"/"dx" (sin x) + sin x "d"/"dx" (x)`
= x cos x + sin x . 1
= x cos x + sin x
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Find `"dy"/"dx"` for the following function
xy – tan(xy)
Find `"dy"/"dx"` for the following function.
x2 – xy + y2 = 1
If `xsqrt(1 + y) + ysqrt(1 + x)` = 0 and x ≠ y, then prove that `"dy"/"dx" = - 1/(x + 1)^2`
Differentiate the following with respect to x.
`sqrt(((x - 1)(x - 2))/((x - 3)(x^2 + x + 1)))`
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Find `"dy"/"dx"` of the following function:
x = a cos3θ, y = a sin3θ
Find y2 for the following function:
y = log x + ax
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
