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Question
Find `"dy"/"dx"` of the following function:
x = ct, y = `c/t`
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Solution
x = ct, y = `"c"/"t"`
`"dx"/"dt"` = c `"dy"/"dt" = "c"((-1)/"t"^2)`
`"dy"/"dt" = ("dy"/"dt")/("dx"/"dt") = ("c"((-1)/"t"^2))/"c" = (-1)/t^2`
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