Advertisements
Advertisements
Question
Find y2 for the following function:
y = e3x+2
Advertisements
Solution
y = e3x+2
`y_1 = "dy"/"dx" = e^(3x + 2) "d"/"dx" (3x + 2)`
`= e^(3x + 2) (3(1) + 0)`
= `3e^(3x + 2)`
`y_2 = ("d"^2"y")/"dx"^2`
`= 3 ["d"/"dx" (e^(3x + 2))]`
= 3`[3e^(3x + 2)]`
= 9`e^(3x + 2)`
= 9y
APPEARS IN
RELATED QUESTIONS
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
Differentiate the following with respect to x.
sin(x2)
Find `"dy"/"dx"` for the following function
xy – tan(xy)
Differentiate the following with respect to x.
xsin x
Differentiate the following with respect to x.
`sqrt(((x - 1)(x - 2))/((x - 3)(x^2 + x + 1)))`
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
Differentiate sin2x with respect to x2.
Find y2 for the following function:
y = log x + ax
